2cos^2x+4cosx=3sin^2x

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Solution for 2cos^2x+4cosx=3sin^2x equation: 


Simplifying
2cos2x + 4cosx = 3sin2x

Reorder the terms:
4cosx + 2cos2x = 3sin2x

Solving
4cosx + 2cos2x = 3in2sx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Combine like terms: 3in2sx + -3in2sx = 0
4cosx + 2cos2x + -3in2sx = 0

Factor out the Greatest Common Factor (GCF), 'sx'.
sx(4co + 2cos + -3in2) = 0


Subproblem 1
Set the factor 'sx' equal to zero and attempt to solve:

Simplifying
sx = 0

Solving
sx = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1sx' to each side of the equation.
sx + -1sx = 0 + -1sx
Remove the zero:
0 = -1sx

Simplifying
0 = -1sx

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Subproblem 2
Set the factor '(4co + 2cos + -3in2)' equal to zero and attempt to solve:

Simplifying
4co + 2cos + -3in2 = 0

Solving
4co + 2cos + -3in2 = 0

Move all terms containing c to the left, all other terms to the right.

Add '3in2' to each side of the equation.
4co + 2cos + -3in2 + 3in2 = 0 + 3in2

Combine like terms: -3in2 + 3in2 = 0
4co + 2cos + 0 = 0 + 3in2
4co + 2cos = 0 + 3in2
Remove the zero:
4co + 2cos = 3in2

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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